College

We appreciate your visit to The following two way table shows the distribution of pets in a large apartment building begin array c c c c hline text Pets text. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

The following two-way table shows the distribution of pets in a large apartment building:

\[
\begin{array}{|c|c|c|c|}
\hline
\text{Pets} & \text{Dog} & \text{No Dog} & \text{Total} \\
\hline
\text{Cat} & 27 & 25 & 52 \\
\hline
\text{No Cat} & 3 & 45 & 48 \\
\hline
\text{Total} & 30 & 70 & 100 \\
\hline
\end{array}
\]

Suppose we select a resident of the apartment building at random. Let event \( A \) = Cat and event \( B \) = Dog. Calculate and interpret \( P(A|B) \).

The probability that a randomly selected resident owns a cat, given that the person also owns a dog, is equal to approximately \(\frac{27}{30}\) or 0.9.

Answer :

Answer:

The probability that a randomly selected resident owns a

✔ cat

, given that the person also owns a

✔ dog

, is equal to approximately

✔ 0.90

.

Step-by-step explanation:

Just did it on edge.

Next slide answer is:

The probability that a randomly selected resident owns a

✔ dog

, given that the person also owns a

✔ cat

, is equal to approximately

✔ 0.519

.

Thanks for taking the time to read The following two way table shows the distribution of pets in a large apartment building begin array c c c c hline text Pets text. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada

Final answer:

When we randomly select a resident who owns a dog, there's a 90% chance that this resident also owns a cat.

Explanation:

The given table shows the distribution of pets in an apartment building. We are looking to find P(A|B), where event A is owning a cat, and event B is owning a dog. This probability indicates the chance that a randomly selected resident owns a cat, given that they already own a dog. We find this by dividing the number of residents who own both a dog and a cat by the total number of residents who own a dog.

From the given table, we know that 27 residents own both a cat and a dog. Whereas, 30 residents own a dog (regardless of whether or not they also own a cat). Hence, P(A|B) can be calculated as follows:

P(A|B) = Number of residents owning both a cat and a dog / Total number of residents owning a dog

= 27/30 = 0.9

Therefore, given that a resident owns a dog, the probability that they also own a cat is 0.9 or 90%.

Learn more about Probability here:

https://brainly.com/question/32117953

#SPJ3