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If a 63 kg person on a 17 kg sled is pushed by two people, one with a force of 152 N and the other with a force of 103 N, what will be the person's acceleration?

Answer :

Final answer:

The acceleration of the 63 kg person on a 17 kg sled being pushed by two people with forces of 152 N and 103 N is 3.1875 m/s², calculated using Newton's second law of motion.

Explanation:

To calculate the acceleration of the person on the sled being pushed by two people, we can apply Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting upon it and inversely proportional to its mass, which can be expressed by the equation F = ma (force equals mass times acceleration).

First, we need to determine the total mass being accelerated, which is the combined mass of the person and the sled: 63 kg + 17 kg = 80 kg. Next, we find the total force exerted by adding the forces applied by the two people: 152 N + 103 N = 255 N. Now, we can use the previously mentioned formula to find the acceleration a by rearranging it to a = F/m.

So the acceleration a equals the total force 255 N divided by the total mass 80 kg, which gives us an acceleration of 3.1875 m/s². Note that we ignored friction and air resistance as the problem does not provide any coefficients or additional forces to consider.

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Rewritten by : Barada

Final answer:

The person's acceleration is 3.09 m/s².


Explanation:

To determine the person's acceleration, we need to calculate the net force acting on the person-sled system using Newton's second law of motion, F = ma. The total force is the sum of the forces applied by the two people, so F = 152 N + 103 N = 255 N. Next, we can calculate the acceleration by rearranging the formula: a = F/m = 255 N / (63 kg + 17 kg) = 3.09 m/s².


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