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Use the standard algorithm to find [tex]3,135 \div 15[/tex].

1. How many times does 15 go into 31?
- 2 times, with a remainder of 1.

2. How many times does 15 go into 13?
- 0 times, with a remainder of 13.

3. Continue the division:
- 15 into 135?
- 9 times, with no remainder.

Therefore, [tex]3,135 \div 15 = 209[/tex].

Answer :

Final answer:

To find 3,135 ÷ 15 using the standard algorithm, divide each digit of the dividend by the divisor step by step and record the quotients.


Explanation:

To find 3,135 ÷ 15 using the standard algorithm, start by dividing 15 into the first digit of the dividend, which is 3. 15 goes into 3 zero times, so the quotients will be 0. We then bring down the next digit, which is 1, and divide 15 into 13. 15 goes into 13 zero times, so the quotient remains 0. Lastly, we bring down the last digit, which is 5, and divide 15 into 35. 15 goes into 35 twice, so the quotient is 2. The final quotient is 203.


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Rewritten by : Barada

To divide 3,135 by 15, we find that 15 goes into 31, 2 times with a remainder of 1, 0 times into 13, and exactly 9 times into 135, resulting in a quotient of 209.

To divide 3,135 by 15 using the standard algorithm, we'll follow these steps:

Determine how many times 15 goes into 31. Since 15 x 2 is 30, and that's the closest we can get to 31 without going over, 15 goes into 31 2 times with a remainder of 1.

Bring down the next digit, which is 3, making the number 13. Since 15 does not go into 13, we write 0 times for this step, with a remainder of 13.

Now we bring down the next digit, which is 5, making the number 135. 15 goes into 135 exactly 9 times with a remainder of 0.

Therefore, the quotient is 209 with a remainder of 0, or simply 209.