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A roller coaster with a potential energy of [tex]$235,200 J$[/tex] sits at the top of a 30 m high hill. What is the mass of the roller coaster?



(Formula: [tex]PE = mgh[/tex])



A. 800 kg

B. 7,840 kg

C. 8,000 kg

D. 78,400 kg

Answer :

We start with the formula for potential energy:
$$
PE = m \cdot g \cdot h,
$$
where
- $PE$ is the potential energy,
- $m$ is the mass,
- $g$ is the acceleration due to gravity, and
- $h$ is the height.

Given:
- $PE = 235\,200 \, J$,
- $g = 9.8 \, m/s^2$, and
- $h = 30 \, m$.

We need to find the mass $m$. Rearranging the formula for $m$ gives:
$$
m = \frac{PE}{g \cdot h}.
$$

Substitute the given values:
$$
m = \frac{235\,200}{9.8 \times 30}.
$$

First, calculate the product in the denominator:
$$
9.8 \times 30 = 294.
$$

Then, compute the mass:
$$
m = \frac{235\,200}{294} = 800 \, \text{kg}.
$$

Thus, the mass of the roller coaster is $\boxed{800 \, kg}$.

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Rewritten by : Barada