College

We appreciate your visit to If you add a metal piece with a temperature of 98 2 C and a mass of 5 65 g to 250 g of 22. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

If you add a metal piece with a temperature of 98.2 °C and a mass of 5.65 g to 250 g of 22.2 °C water in a calorimeter that absorbs no heat, what is the heat capacity of the unknown metal piece if the final temperature of the solution is 34 °C?

Answer :

Final answer:

To find the heat capacity of the unknown metal piece, use the equation Q = mcΔT. Calculate the heat energy absorbed by the water and the metal piece separately, then set them equal to each other to solve for the unknown specific heat capacity of the metal.


Explanation:

To find the heat capacity of the unknown metal piece, we can use the equation Q = mcΔT, where Q is the heat energy absorbed or released, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

First, let's calculate the heat energy absorbed by the water using the equation Q_water = mc(ΔT_water), where m_water is the mass of water, c_water is the specific heat capacity of water, and ΔT_water is the change in temperature of water. Substituting the given values, we get Q_water = 250 g * 4.18 J/g°C * (34°C - 22.2°C).

Next, let's calculate the heat energy absorbed by the metal piece using the same equation Q_metal = mc(ΔT_metal). Substituting the given values, we get Q_metal = 5.65 g * c_metal * (34°C - 98.2°C).

Since there is no heat transfer to the calorimeter, the heat energy absorbed by the water will be equal to the heat energy absorbed by the metal piece, so we can set up the equation Q_water = Q_metal. Solving for c_metal, we get c_metal = (250 g * 4.18 J/g°C * (34°C - 22.2°C)) / (5.65 g * (34°C - 98.2°C)).

After evaluating the expression, the heat capacity of the unknown metal piece is found to be approximately 1.89 J/g°C.


Learn more about heat capacity here:

https://brainly.com/question/28302909


Thanks for taking the time to read If you add a metal piece with a temperature of 98 2 C and a mass of 5 65 g to 250 g of 22. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada

The heat capacity of the unknown metal piece is approximately 99.94 J/g°C.

The heat capacity of the unknown metal piece can be determined using the equation:

Q = mcΔT

Where:

Q = amount of heat transferred

m = mass of the metal

c = specific heat capacity of the metal

ΔT = change in temperature

In this case, we have:

Q = 6.64 kJ = 6,640 J

m = 5.65 g

ΔT = (34 °C - 22.2 °C) = 11.8 °C

Substituting the known values into the equation:

6,640 J = (5.65 g) * c * 11.8 °C

Solving for c:

c = 6,640 J / (5.65 g * 11.8 °C)

c ≈ 99.94 J/g°C

Therefore, the heat capacity of the unknown metal piece is approximately 99.94 J/g°C.