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Can you place the digits 1 through 9 into a 3-by-3 square so that each row, column, and diagonal add up to the same total? Four digits have been inserted.

1
8
7

A.
673
159
824

B.
672
159
834

C.
679
152
834

D.
276
159
834

Answer :

Final answer:

The correct answer to placing digits 1 through 9 in a 3-by-3 square to form a magic square is option B, as it is the only configuration where the sum of each row, column, and diagonal equals 15. Therefore, the correct answer is B.

Explanation:

The question asks if we can place the digits 1 through 9 into a 3-by-3 square so that the sum of the numbers in each row, column, and diagonal are equal.

This is known as a magic square. Based on the options provided, we can determine the correct configuration by ensuring the sums of each row, column, and diagonal are equal.

Upon examination, option B correctly forms a magic square:

  • 6 + 7 + 2 = 15
  • 1 + 5 + 9 = 15
  • 8 + 3 + 4 = 15
  • 6 + 1 + 8 (Vertical) = 15
  • 7 + 5 + 3 (Vertical) = 15
  • 2 + 9 + 4 (Vertical) = 15
  • 6 + 5 + 4 (Diagonal) = 15
  • 2 + 5 + 8 (Diagonal) = 15

Therefore, the correct answer is B. 6,7,2; 1,5,9; 8,3,4 form a magic square, where every row, column, and both diagonals add up to the same total, which in this case is 15.

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