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Answer :
Answer:
94.05 mV
Step-by-step explanation:
N = Number of turns = 149
r = Radius of coil = 2.45 cm = 0.0245 m
t = Time = 0.141 s
Initial magnetic field = 50.9 mT
Final magnetic field = 98.1 mT
A = Area = πr² = π×0.0245²
[tex]\text{Induced emf}=NA\frac{dB}{dt}\\\Rightarrow \text{Induced emf}=149\times \pi \times 0.0245^2\frac{(98.1-50.9)\times 10^{-3}}{0.141}\\\Rightarrow \text{Induced emf}=0.09405 V = 94.05 mV[/tex]
∴ Magnitude of the average EMF, that is induced in the coil during this time interval is 94.05 mV
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