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Answer :
To prepare a 0.5 M sodium hydroxide solution in 1000 mL using pellets with a 96% assay, follow these steps:
1. Calculate the number of moles of NaOH needed for 1 L of a 0.5 M solution using the formula
[tex]$$
n = C \times V,
$$[/tex]
where [tex]$C = 0.5\ \text{M}$[/tex] and [tex]$V = 1\ \text{L}$[/tex]. This gives
[tex]$$
n = 0.5 \times 1 = 0.5\ \text{moles}.
$$[/tex]
2. Determine the mass of pure NaOH required. The molar mass of NaOH is about [tex]$40\ \text{g/mol}$[/tex], so the mass is calculated as
[tex]$$
m = n \times \text{Molar mass} = 0.5\ \text{moles} \times 40\ \frac{\text{g}}{\text{mol}} = 20\ \text{g}.
$$[/tex]
3. Since the pellets are only 96% pure, you need to use a larger mass to obtain 20 g of pure NaOH. The required mass of pellets is
[tex]$$
m_{\text{pellets}} = \frac{m}{\text{Assay}} = \frac{20\ \text{g}}{0.96} \approx 20.83\ \text{g}.
$$[/tex]
4. Perform the solution preparation with the following procedure:
- Weigh out approximately [tex]$20.83\ \text{g}$[/tex] of sodium hydroxide pellets.
- Place the pellets into a beaker containing less than 1000 mL of distilled water.
- Stir the mixture vigorously until all the pellets are completely dissolved.
- Transfer the dissolved solution into a 1000 mL volumetric flask.
- Rinse the beaker with distilled water and add the rinsings to the flask to ensure complete transfer.
- Fill the volumetric flask with distilled water up to the 1000 mL mark and mix thoroughly to ensure homogeneity.
By following these steps, you will have prepared a 0.5 M NaOH solution in 1000 mL using sodium hydroxide pellets with a 96% assay.
1. Calculate the number of moles of NaOH needed for 1 L of a 0.5 M solution using the formula
[tex]$$
n = C \times V,
$$[/tex]
where [tex]$C = 0.5\ \text{M}$[/tex] and [tex]$V = 1\ \text{L}$[/tex]. This gives
[tex]$$
n = 0.5 \times 1 = 0.5\ \text{moles}.
$$[/tex]
2. Determine the mass of pure NaOH required. The molar mass of NaOH is about [tex]$40\ \text{g/mol}$[/tex], so the mass is calculated as
[tex]$$
m = n \times \text{Molar mass} = 0.5\ \text{moles} \times 40\ \frac{\text{g}}{\text{mol}} = 20\ \text{g}.
$$[/tex]
3. Since the pellets are only 96% pure, you need to use a larger mass to obtain 20 g of pure NaOH. The required mass of pellets is
[tex]$$
m_{\text{pellets}} = \frac{m}{\text{Assay}} = \frac{20\ \text{g}}{0.96} \approx 20.83\ \text{g}.
$$[/tex]
4. Perform the solution preparation with the following procedure:
- Weigh out approximately [tex]$20.83\ \text{g}$[/tex] of sodium hydroxide pellets.
- Place the pellets into a beaker containing less than 1000 mL of distilled water.
- Stir the mixture vigorously until all the pellets are completely dissolved.
- Transfer the dissolved solution into a 1000 mL volumetric flask.
- Rinse the beaker with distilled water and add the rinsings to the flask to ensure complete transfer.
- Fill the volumetric flask with distilled water up to the 1000 mL mark and mix thoroughly to ensure homogeneity.
By following these steps, you will have prepared a 0.5 M NaOH solution in 1000 mL using sodium hydroxide pellets with a 96% assay.
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