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Answer :
Final answer:
The height of the rocket at 35.9 s can be calculated using the equation for vertical motion.
Explanation:
The height of the rocket at 35.9 s can be calculated using the equation for vertical motion. Since we know the initial vertical velocity (v₀ = 453 m/s), the time of flight (t = 35.9 s), and the acceleration due to gravity (g = 9.8 m/s²), we can use the formula:
Δy = (v₀ * t) + (1/2 * g * t²)
Plugging in the values, we get:
Δy = (453 * 35.9) + (1/2 * 9.8 * 35.9²)
Simplifying, we find that the height of the rocket at 35.9 s is approximately 256,788.15 m.
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