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Answer :
Given,
Mass of the cannon, m₁=825 kg
Mass of the projectile, m₂=1.12 kg
The velocity of the projectile, v₂=124 m/s
According to the law of conservation of momentum, the momentum of the projectile fired should be equal to the momentum of the cannon.
i.e.,
[tex]m_1v_1=m_2v_2[/tex]Therefore the velocity of the cannon is given by,
[tex]v_1=\frac{m_2v_2}{m_1}[/tex]On substituting the known values in the above equation,
[tex]v_1=\frac{1.12\times124}{825}=0.168\text{ m/s}[/tex]Therefore the velocity of the cannon immediately after the projectile is shot is 0.168 m/s
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