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What is the domain of the function [tex]h[/tex]?

[tex]h(x)=\sqrt{x-7}+5[/tex]

A. [tex]x \geq 7[/tex]

B. [tex]x \geq 5[/tex]

C. [tex]x \leq -7[/tex]

D. [tex]x \leq 5[/tex]

Answer :

To determine the domain of the function

[tex]$$
h(x) = \sqrt{x-7} + 5,
$$[/tex]

we need to ensure that the expression inside the square root is non-negative, because the square root of a negative number is not defined in the set of real numbers. This requirement leads us to the inequality

[tex]$$
x - 7 \geq 0.
$$[/tex]

To solve this inequality, add 7 to both sides:

[tex]$$
x \geq 7.
$$[/tex]

Thus, the function is defined for all real numbers [tex]$x$[/tex] such that [tex]$x$[/tex] is greater than or equal to [tex]$7$[/tex]. This corresponds to option A, which states [tex]$x \geq 7$[/tex].

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