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In the electrolysis of aluminum chloride, 10 A of electricity was passed for 96.5 seconds. Calculate the mass in grams of aluminum deposited.

Given:
- [tex]\text{Al} = 27[/tex]
- [tex]\text{Cl} = 35.5[/tex]
- [tex]F = 96500 \text{ C/mol}[/tex]

Options:
(a) 0.21
(b) 0.09
(c) 0.27
(d) 0.45

Answer :

The mass in gram of aluminum deposited (c) 0.27 g.

Steps

The balanced chemical equation for the electrolysis of aluminum chloride is:

2 AlCl3 → 2 Al + 3 Cl2

From this equation, we can see that 2 moles of Al will be produced for every 2 moles of AlCl3 consumed. The molar mass of Al is 27 g/mol, so the mass of Al produced can be calculated using the following formula:

mass of Al = (current × time × molar mass of Al) / (3 × Faraday's constant)

where the current is in amperes, time is in seconds, Faraday's constant is in coulombs per mole of electrons (F = 96500 C), and the factor of 3 in the denominator comes from the stoichiometry of the reaction.

Plugging in the values given in the problem, we get:

mass of Al = (10 A × 96.5 s × 27 g/mol) / (3 × 96500 C/mol) = 0.27 g

Therefore, the answer is (c) 0.27 g.

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