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Answer :
The mass in gram of aluminum deposited (c) 0.27 g.
Steps
The balanced chemical equation for the electrolysis of aluminum chloride is:
2 AlCl3 → 2 Al + 3 Cl2
From this equation, we can see that 2 moles of Al will be produced for every 2 moles of AlCl3 consumed. The molar mass of Al is 27 g/mol, so the mass of Al produced can be calculated using the following formula:
mass of Al = (current × time × molar mass of Al) / (3 × Faraday's constant)
where the current is in amperes, time is in seconds, Faraday's constant is in coulombs per mole of electrons (F = 96500 C), and the factor of 3 in the denominator comes from the stoichiometry of the reaction.
Plugging in the values given in the problem, we get:
mass of Al = (10 A × 96.5 s × 27 g/mol) / (3 × 96500 C/mol) = 0.27 g
Therefore, the answer is (c) 0.27 g.
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