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Answer :
We have that the original pressure of this gas is mathematically given as
P2=17.854 kPa
Boyle's law
Question Parameters:
AT constant temperature, a gas is compressed from 5.5 L to 1 L.
At 1 L, the pressure of the gas is 98.2 kPa
Generally the equation for Boyle's law is mathematically given as
P1V1=P2V2
Therefore
[tex]P1=\frac{P2V2}{V1}\\\\P2=\frac{98.2*1}{5.5}[/tex]
P2=17.854 kPa
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