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a.) Solve for \( n \):

1. \( 40 - 8 = 40 + n \)

What is \( n \)?

2. \( 25 + (-100) = 25 - n \)

What is \( n \)?

Answer :

[tex]\begin{gathered} a)n=-8 \\ b)n=100 \end{gathered}[/tex]

Explanation

Step 1

a)

[tex]40-8=40+n[/tex]

add like terms

[tex]\begin{gathered} 40-8=40+n \\ 32=40+n \end{gathered}[/tex]

now, subtract 40 in both sides to isolate n

[tex]\begin{gathered} 32=40+n \\ 32-40=40+n-40 \\ -8=n \\ n=-8 \end{gathered}[/tex]

Step 2

b)

[tex]\begin{gathered} 25+(-100)=25-n \\ break\text{ the parenthesis by multipling +}\cdot-100 \\ 25+(-100)=25-n \\ 25-100=25-n \\ \text{add like terms} \\ -75=25-n \\ \text{subtract 25 in both sides} \\ -75-25=25-n-25 \\ -100=-n \\ \text{Multiply both sides by -1} \\ -100\cdot-1=-n\cdot-1 \\ 100=n \\ n=100 \end{gathered}[/tex]

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