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Rob has 40 coins, consisting of dimes and quarters. The total value of his coins is $7.60. How many dimes and quarters does Rob have? Show your work.

Answer :

Rob has 16 dimes and 24 quarters.

Rob has 40 coins consisting of dimes and quarters, and the total value is $7.60. Let's set up the following variables:

d = number of dimes

q = number of quarters

We need two equations based on the given information:

Equation for the total number of coins: d + q = 40

Equation for the total value in cents (1 dime = 10 cents, 1 quarter = 25 cents): 10d + 25q = 760

Now let's solve these equations step by step:

Step 1: Solve for one variable

From the first equation, solve for d:

d = 40 - q

Step 2: Substitute into the second equation

Substitute d into the second equation:

10(40 - q) + 25q = 760

Distribute the 10:

400 - 10q + 25q = 760

Combine like terms:

15q = 360

Solve for q:

q = 24

Step 3: Find the number of dimes

Substitute q back into the first equation:

d + 24 = 40

Solve for d:

d = 16

So, Rob has 16 dimes and 24 quarters.

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Rewritten by : Barada

Answer:

Let d = the number of dimes. Then the number of quarters is (40-d). The dimes contribute 10d cents to the total. The quarters contribute 25*(40-d) cents to the total. The "value" equation is 10d + 25*(40-d) = 760. Simplify and solve for x: 10d + 1000 - 25d = 760, or -15d = 1000-660 ---> -15d = -240. d =  = 16. Answer. 16 dimes and 40-16 = 24 quarters. by ikleyn(36377)

Step-by-step explanation:

Let d = the number of dimes. Then the number of quarters is (40-d). The dimes contribute 10d cents to the total. The quarters contribute 25*(40-d) cents to the total. The "value" equation is 10d + 25*(40-d) = 760. Simplify and solve for x: 10d + 1000 - 25d = 760, or -15d = 1000-660 ---> -15d = -240. d =  = 16. Answer. 16 dimes and 40-16 = 24 quarters. by ikleyn(36377)