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Answer :
Rob has 16 dimes and 24 quarters.
Rob has 40 coins consisting of dimes and quarters, and the total value is $7.60. Let's set up the following variables:
d = number of dimes
q = number of quarters
We need two equations based on the given information:
Equation for the total number of coins: d + q = 40
Equation for the total value in cents (1 dime = 10 cents, 1 quarter = 25 cents): 10d + 25q = 760
Now let's solve these equations step by step:
Step 1: Solve for one variable
From the first equation, solve for d:
d = 40 - q
Step 2: Substitute into the second equation
Substitute d into the second equation:
10(40 - q) + 25q = 760
Distribute the 10:
400 - 10q + 25q = 760
Combine like terms:
15q = 360
Solve for q:
q = 24
Step 3: Find the number of dimes
Substitute q back into the first equation:
d + 24 = 40
Solve for d:
d = 16
So, Rob has 16 dimes and 24 quarters.
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Rewritten by : Barada
Answer:
Let d = the number of dimes. Then the number of quarters is (40-d). The dimes contribute 10d cents to the total. The quarters contribute 25*(40-d) cents to the total. The "value" equation is 10d + 25*(40-d) = 760. Simplify and solve for x: 10d + 1000 - 25d = 760, or -15d = 1000-660 ---> -15d = -240. d =  = 16. Answer. 16 dimes and 40-16 = 24 quarters. by ikleyn(36377)
Step-by-step explanation:
Let d = the number of dimes. Then the number of quarters is (40-d). The dimes contribute 10d cents to the total. The quarters contribute 25*(40-d) cents to the total. The "value" equation is 10d + 25*(40-d) = 760. Simplify and solve for x: 10d + 1000 - 25d = 760, or -15d = 1000-660 ---> -15d = -240. d =  = 16. Answer. 16 dimes and 40-16 = 24 quarters. by ikleyn(36377)