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Answer :
Thus, in 37.6 g of 70.5 wt% aqueous perchloric acid:
- There are 26.508 g of HClO₄.
- There are 11.092 g of water.
To find the amount of perchloric acid (HClO₄) and water in the solution, we'll use the given weight percentage.
Given:
- Total weight of the solution = 37.6 g
- Weight percentage of HClO₄ = 70.5%
First, we calculate the mass of HClO₄ in the solution:
[tex]\[ \text{Mass of HClO}_4 = \text{Total mass} \times \text{Weight percentage of HClO}_4 \][/tex]
[tex]\[ \text{Mass of HClO}_4 = 37.6 \, \text{g} \times \frac{70.5}{100} \][/tex]
[tex]\[ \text{Mass of HClO}_4 = 37.6 \, \text{g} \times 0.705 \][/tex]
[tex]\[ \text{Mass of HClO}_4 = 26.508 \, \text{g} \][/tex]
Next, we calculate the mass of water in the solution. Since the weight percentage of H₂O is the complement of the weight percentage of HClO₄:
[tex]\[ \text{Weight percentage of H}_2\text{O} = 100\% - 70.5\% = 29.5\% \][/tex]
Now, we calculate the mass of water:
[tex]\[ \text{Mass of H}_2\text{O} = \text{Total mass} \times \text{Weight percentage of H}_2\text{O} \][/tex]
[tex]\[ \text{Mass of H}_2\text{O} = 37.6 \, \text{g} \times \frac{29.5}{100} \][/tex]
[tex]\[ \text{Mass of H}_2\text{O} = 37.6 \, \text{g} \times 0.295 \][/tex]
[tex]\[ \text{Mass of H}_2\text{O} = 11.092 \, \text{g} \][/tex]
Thus, in 37.6 g of 70.5 wt% aqueous perchloric acid:
- There are 26.508 g of HClO₄.
- There are 11.092 g of water.
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Answer :
The mass of perchloric acid is, 26.5 grams.
The mass of water in the same solution is, 11.1 grams
Explanation :
As we are given that 70.5 wt % aqueous perchloric acid that means 70.5 grams of perchloric acid present in 100 grams of solution.
Now we have to determine the mass of perchloric acid in 37.6 grams of aqueous perchloric acid.
As, 100 grams of aqueous perchloric acid (solution) contains 70.5 grams of perchloric acid.
So, 37.6 grams of aqueous perchloric acid (solution) contains [tex]\frac{37.6}{100}\times 70.5=26.5[/tex] grams of perchloric acid.
Thus, the mass of perchloric acid is, 26.5 grams.
Now we have to determine the mass of water are in the same solution.
Total mass of solution = 37.6 g
Mass of perchloric acid = 26.5 g
Mass of water = Total mass of solution - Mass of perchloric acid
Mass of water = 37.6 g - 26.5 g
Mass of water = 11.1 g
Thus, the mass of water in the same solution is, 11.1 grams