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Answer :
We start with the exponential equation
$$
2^x = 128.
$$
To rewrite this equation in logarithmic form, we take the logarithm with base 2 of both sides of the equation. Doing so, we use the property that if
$$
a^b = c,
$$
then
$$
b = \log_a{c}.
$$
Thus, for our equation we have:
$$
x = \log_2{128}.
$$
This means that the logarithmic form of the equation is:
$$
\log_2{128} = x.
$$
Comparing with the multiple choice options, the correct choice is option 3:
$$
\log_2 128 = x.
$$
$$
2^x = 128.
$$
To rewrite this equation in logarithmic form, we take the logarithm with base 2 of both sides of the equation. Doing so, we use the property that if
$$
a^b = c,
$$
then
$$
b = \log_a{c}.
$$
Thus, for our equation we have:
$$
x = \log_2{128}.
$$
This means that the logarithmic form of the equation is:
$$
\log_2{128} = x.
$$
Comparing with the multiple choice options, the correct choice is option 3:
$$
\log_2 128 = x.
$$
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Rewritten by : Barada
