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Josiah invests [tex]\$360[/tex] into an account that accrues [tex]3\%[/tex] interest annually. Assuming no deposits or withdrawals are made, which equation represents the amount of money in Josiah's account, [tex]y[/tex], after [tex]x[/tex] years?

A. [tex]y = 360(1.3)^x[/tex]

B. [tex]y = 360(0.3)^x[/tex]

C. [tex]y = 360(0.03)^x[/tex]

D. [tex]y = 360(1.03)^x[/tex]

Answer :

To find the equation that represents the amount of money in Josiah's account after a certain number of years, we need to use the formula for compound interest. The formula for the future value [tex]\( y \)[/tex] of an investment is:

[tex]\[ y = P(1 + r)^x \][/tex]

Where:
- [tex]\( y \)[/tex] is the future value of the investment,
- [tex]\( P \)[/tex] is the principal amount (initial investment),
- [tex]\( r \)[/tex] is the annual interest rate (expressed as a decimal),
- [tex]\( x \)[/tex] is the number of years the money is invested.

Given:
- The principal amount [tex]\( P = 360 \)[/tex] dollars,
- The annual interest rate [tex]\( r = 3\% = 0.03 \)[/tex],
- The time in years is [tex]\( x \)[/tex].

Plug these values into the formula:

[tex]\[ y = 360(1 + 0.03)^x \][/tex]

Simplify the equation:

[tex]\[ y = 360(1.03)^x \][/tex]

So, the equation that represents the amount of money in Josiah's account after [tex]\( x \)[/tex] years is:

[tex]\[ y = 360(1.03)^x \][/tex]

Therefore, the correct choice is:

[tex]\( y = 360(1.03)^x \)[/tex]

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