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Answer :
Sure! Let's go through the genetics problem step-by-step.
First Scenario:
- We have a heterozygous male with the genotype [tex]\(Ww\)[/tex] and a homozygous recessive female with the genotype [tex]\(ww\)[/tex].
- The possible combinations of their alleles during reproduction are as follows:
[tex]\[
\begin{array}{|c|c|c|}
\hline & w & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]
- From this table, we can see the potential offspring genotypes: [tex]\( Ww, ww, Ww, ww \)[/tex].
- Out of these four possibilities, two are [tex]\(Ww\)[/tex], which are heterozygous.
- Therefore, there is a [tex]\(\frac{2}{4} = \frac{1}{2} = 0.5\)[/tex] or 50% chance that the offspring will be heterozygous.
Second Scenario:
- We have a heterozygous genotype [tex]\(Ww\)[/tex] crossed with a homozygous dominant genotype [tex]\(WW\)[/tex].
- The possible combinations of their alleles are:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\][/tex]
- From this table, we get the potential offspring genotypes: [tex]\( WW, Ww, WW, Ww \)[/tex].
- Since all of these combinations result in either [tex]\(WW\)[/tex] or [tex]\(Ww\)[/tex], there are no homozygous recessive ([tex]\(ww\)[/tex]) offspring.
- Therefore, the probability of having a homozygous recessive offspring is [tex]\(0\%.\)[/tex]
I hope this helps you understand how to solve the problem! If you have any more questions, feel free to ask.
First Scenario:
- We have a heterozygous male with the genotype [tex]\(Ww\)[/tex] and a homozygous recessive female with the genotype [tex]\(ww\)[/tex].
- The possible combinations of their alleles during reproduction are as follows:
[tex]\[
\begin{array}{|c|c|c|}
\hline & w & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]
- From this table, we can see the potential offspring genotypes: [tex]\( Ww, ww, Ww, ww \)[/tex].
- Out of these four possibilities, two are [tex]\(Ww\)[/tex], which are heterozygous.
- Therefore, there is a [tex]\(\frac{2}{4} = \frac{1}{2} = 0.5\)[/tex] or 50% chance that the offspring will be heterozygous.
Second Scenario:
- We have a heterozygous genotype [tex]\(Ww\)[/tex] crossed with a homozygous dominant genotype [tex]\(WW\)[/tex].
- The possible combinations of their alleles are:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\][/tex]
- From this table, we get the potential offspring genotypes: [tex]\( WW, Ww, WW, Ww \)[/tex].
- Since all of these combinations result in either [tex]\(WW\)[/tex] or [tex]\(Ww\)[/tex], there are no homozygous recessive ([tex]\(ww\)[/tex]) offspring.
- Therefore, the probability of having a homozygous recessive offspring is [tex]\(0\%.\)[/tex]
I hope this helps you understand how to solve the problem! If you have any more questions, feel free to ask.
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