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A man weighing 198 lbs drinks 2 beers over the course of 2 hours at a friend’s house. What was his BAC when he drove home?

Answer :

The man's BAC after consuming 2 beers over 2 hours weighed approximately 0.0084%, which is much below the legal limit of 0.08% for driving.

To calculate the man's Blood Alcohol Concentration (BAC), we use the formula:

BAC = (A x 5.14 / W x r) - .015 x H

  1. A is the total alcohol consumed in ounces.
  2. W is the body weight in pounds.
  3. r is the alcohol distribution ratio (0.73 for men).
  4. H is the time since the first drink in hours.

Each beer contains about 0.54 ounces of pure alcohol. For 2 beers:

A = 2 beers x 0.54 ounces = 1.08 ounces

W = 198 lbs

r = 0.73

H = 2 hours

Plugging these values into the formula:

BAC = (1.08 x 5.14 / 198 x 0.73) - .015 x 2

= (5.5512 / 144.54) - 0.03

≈ 0.0384 - 0.03

= 0.0084

Conclusion

The man's BAC when he drove home was approximately 0.0084%, well below the legal limit of 0.08% for driving.

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