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Answer :
Sure, let's break down the problem step-by-step:
1. Given Data:
- Mass of Sully on the snowmobile, [tex]\( m = 280 \)[/tex] kg
- Initial velocity, [tex]\( u = 10 \)[/tex] m/s
- Final velocity, [tex]\( v = 16 \)[/tex] m/s
- Time taken for acceleration, [tex]\( t = 10 \)[/tex] seconds
2. Calculate Acceleration:
The acceleration can be calculated using the formula:
[tex]\[
a = \frac{v - u}{t}
\][/tex]
Plug in the given values:
[tex]\[
a = \frac{16 \text{ m/s} - 10 \text{ m/s}}{10 \text{ s}} = \frac{6 \text{ m/s}}{10 \text{ s}} = 0.6 \text{ m/s}^2
\][/tex]
3. Calculate Force:
Now we can calculate the force using the formula [tex]\( F = ma \)[/tex]:
[tex]\[
F = 280 \text{ kg} \times 0.6 \text{ m/s}^2 = 168 \text{ N}
\][/tex]
So, the force required is [tex]\( 168 \ \text{N} \)[/tex].
Given the options provided, the correct answer is:
- B. [tex]\( 168 \text{ N} \)[/tex]
1. Given Data:
- Mass of Sully on the snowmobile, [tex]\( m = 280 \)[/tex] kg
- Initial velocity, [tex]\( u = 10 \)[/tex] m/s
- Final velocity, [tex]\( v = 16 \)[/tex] m/s
- Time taken for acceleration, [tex]\( t = 10 \)[/tex] seconds
2. Calculate Acceleration:
The acceleration can be calculated using the formula:
[tex]\[
a = \frac{v - u}{t}
\][/tex]
Plug in the given values:
[tex]\[
a = \frac{16 \text{ m/s} - 10 \text{ m/s}}{10 \text{ s}} = \frac{6 \text{ m/s}}{10 \text{ s}} = 0.6 \text{ m/s}^2
\][/tex]
3. Calculate Force:
Now we can calculate the force using the formula [tex]\( F = ma \)[/tex]:
[tex]\[
F = 280 \text{ kg} \times 0.6 \text{ m/s}^2 = 168 \text{ N}
\][/tex]
So, the force required is [tex]\( 168 \ \text{N} \)[/tex].
Given the options provided, the correct answer is:
- B. [tex]\( 168 \text{ N} \)[/tex]
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