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Answer :
Answer:
[tex]V = 0.117 \ L[/tex]
General Formulas and Concepts:
Chem
- Reading a Periodic Table
- Writing compounds and polyatomic ions
- Molarity = moles of solute / liters of solution
Explanation:
Step 1: Define
1.57 M KOH (potassium hydroxide)
10.3 g KOH
Step 2: Define conversions
Molar Mass of K - 39.10 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of KOH - 39.10 + 16.00 + 1.01 = 56.11 g/mol
Step 3: Convert
[tex]10.3 \ g \ KOH(\frac{1 \ mol \ KOH}{56.11 \ g \ KOH} )[/tex] = 0.183568 mol KOH
Step 4: Solve for Volume
- Substitute: [tex]1.57 \ M=\frac{0.183568 \ mol}{x \ L}[/tex]
- Move x: [tex]x1.57 \ M=0.183568 \ mol[/tex]
- Isolate x: [tex]x=\frac{0.183568 \ mol}{1.57 \ M}[/tex]
- Evaluate: [tex]x=0.116922 \ L[/tex]
Step 5: Check
We are given 3 sig figs. Follow sig fig rules.
[tex]0.116922 \ L \approx 0.117 \ L[/tex]
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