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What is the quotient of the following division problem?

[tex]\[
16 \longdiv {1516}
\][/tex]

A. 94 r 13
B. 96 r 11
C. 94 r 12
D. 93 r 11

Answer :

To solve the division problem [tex]\( 1516 \div 16 \)[/tex] and find the quotient and remainder, follow these steps:

1. Start by dividing the first part of the number:
- Look at the first two digits of 1516, which are 15. Divide 15 by 16. Since 15 is smaller than 16, it goes 0 times. So, we don't write anything yet; instead, look at the next digit.

2. Bring down the next digit:
- Combine 15 with the next digit to get 151. Now, divide 151 by 16.

3. Calculate how many times 16 goes into 151:
- 16 goes into 151 a total of 9 times without exceeding 151.
- Multiply 16 by 9 to get 144.
- Subtract 144 from 151 to find the remainder of this step: [tex]\( 151 - 144 = 7 \)[/tex].

4. Bring down the last digit:
- Bring down the next digit, which is 6, to the remainder 7 to make it 76.

5. Divide again:
- Now, see how many times 16 fits into 76.
- 16 goes into 76 a total of 4 times without exceeding 76.
- Multiply 16 by 4 to get 64.
- Subtract 64 from 76 to find the final remainder: [tex]\( 76 - 64 = 12 \)[/tex].

So, the quotient of [tex]\( 1516 \div 16 \)[/tex] is 94, with a remainder of 12.

Therefore, the correct answer is C. 94 r 12.

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