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Answer :
We start by noting that the simulation used 50 random numbers (one for each simulated shot). A shot is considered successful if the random number is between 1 and 40 (inclusive), representing a 40% chance. In the simulation, 18 out of the 50 numbers fell in this range.
Thus, the proportion of successful shots in the simulation is calculated by
[tex]$$
\text{Proportion} = \frac{18}{50} \times 100\% = 36\%.
$$[/tex]
In the game, Mike made 17 out of 50 shots, which is
[tex]$$
\frac{17}{50} \times 100\% = 34\%.
$$[/tex]
This indicates that in the simulation, approximately 36% of the shots were “made.” Since 36% is lower than the claimed 40%, this one simulation does not fully support Mike's claim. Moreover, the simulated success rate is close to the observed shooting percentage (34%), suggesting that Mike’s shooting performance might be lower than he claims.
Thus, the final answer is:
[tex]$$
36.0\%; \text{ This one simulation does not fully support Mike's claim, as the simulated success rate is lower than the claimed } 40\% \text{ and is close to the observed shooting percentage of } 34.0\%.
$$[/tex]
Thus, the proportion of successful shots in the simulation is calculated by
[tex]$$
\text{Proportion} = \frac{18}{50} \times 100\% = 36\%.
$$[/tex]
In the game, Mike made 17 out of 50 shots, which is
[tex]$$
\frac{17}{50} \times 100\% = 34\%.
$$[/tex]
This indicates that in the simulation, approximately 36% of the shots were “made.” Since 36% is lower than the claimed 40%, this one simulation does not fully support Mike's claim. Moreover, the simulated success rate is close to the observed shooting percentage (34%), suggesting that Mike’s shooting performance might be lower than he claims.
Thus, the final answer is:
[tex]$$
36.0\%; \text{ This one simulation does not fully support Mike's claim, as the simulated success rate is lower than the claimed } 40\% \text{ and is close to the observed shooting percentage of } 34.0\%.
$$[/tex]
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