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Given that the mean of [tex]$16, w, 17, 9, x, 2, y, 7,$[/tex] and [tex]$z$[/tex] is 11, find the mean of [tex]$w, x, y,$[/tex] and [tex][tex]$z$[/tex][/tex].

Answer :

We are given that the mean of the numbers
[tex]$$16,\, w,\, 17,\, 9,\, x,\, 2,\, y,\, 7,$$[/tex]
and [tex]$$z$$[/tex]
is 11. Since there are 9 numbers in total, the total sum of all the numbers is
[tex]$$\text{Total Sum} = 11 \times 9 = 99.$$[/tex]

Next, we identify the known numbers:
[tex]$$16,\, 17,\, 9,\, 2,\, 7.$$[/tex]
Their sum is:
[tex]$$16 + 17 + 9 + 2 + 7 = 51.$$[/tex]

Now, let [tex]$S$[/tex] be the sum of the unknown variables [tex]$w,\, x,\, y,\, z$[/tex]. Then,
[tex]$$S = \text{Total Sum} - \text{Sum of known numbers} = 99 - 51 = 48.$$[/tex]

Since there are 4 unknown numbers ([tex]$w, x, y,$[/tex] and [tex]$z$[/tex]), their mean is calculated as:
[tex]$$\text{Mean of } w,\, x,\, y,\, z = \frac{S}{4} = \frac{48}{4} = 12.$$[/tex]

Thus, the mean of [tex]$w, x, y, z$[/tex] is
[tex]$$\boxed{12}.$$[/tex]

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