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A medical assistant is preparing [tex]1 \, \text{g/kg}[/tex] of activated charcoal for a patient who weighs 176 lbs. How many grams of charcoal should the medical assistant prepare?

Answer :

Final answer:

To find how many grams of activated charcoal to prepare for a 176-pound patient at a dosage of 1g/kg, first convert pounds to kilograms, then multiply by the dosage ratio. The patient weighs approximately 79.832 kg, and therefore, around 80 grams of activated charcoal should be prepared.

Explanation:

The question asks how many grams of activated charcoal should be prepared for a patient weighing 176 pounds (lbs) when the dosage is 1 gram per kilogram (kg) of body weight. First, we need to convert the patient's weight from pounds to kilograms, knowing that 1 pound is equivalent to 0.453592 kilograms.

Using this conversion, we calculate that 176 pounds is approximately 79.832 kilograms (176 lbs × 0.453592 kg/lb).

Next, we calculate the needed dosage of activated charcoal by multiplying the patient's weight in kilograms by the dosage ratio, which is 1 g/kg. Thus, the medical assistant should prepare:

79.832 kg × 1 g/kg = 79.832 grams of activated charcoal.

This is rounded to the nearest whole number, so 80 grams of activated charcoal should be prepared for the patient.

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