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Answer :
2.4 more miles to reach the goal of 4 miles that week
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Molly needs to run an additional [tex]\(2 \frac{2}{5}\)[/tex] miles to reach her goal.
Molly has already run [tex]\(1 \frac{3}{5}\)[/tex] miles. We need to subtract this from her weekly goal of 4 miles. First, let's convert 4 and [tex]\(1 \frac{3}{5}\)[/tex] to fractions with the same denominator.
Molly's weekly goal is 4 miles:
[tex]\[ 4 = \frac{4 \times 5}{1 \times 5} = \frac{20}{5} \][/tex]
She has already run [tex]\(1 \frac{3}{5}\)[/tex] miles, which we previously converted to an improper fraction:
[tex]\[ 1 \frac{3}{5} = \frac{8}{5} \][/tex]
Now, let's subtract the distance she has already run from her weekly goal:
[tex]\[ \frac{20}{5} - \frac{8}{5} = \frac{20 - 8}{5} = \frac{12}{5} \][/tex]
So, the number of miles Molly still needs to run in order to reach her goal for this week is [tex]\frac{12}{5}}.[/tex]
Or, if you prefer to convert it to a mixed number:
[tex]\[ \frac{12}{5} = 2 \frac{2}{5} \][/tex]
So, she needs to run an additional [tex]\(2 \frac{2}{5}\)[/tex] miles to reach her goal.