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The population, [tex]p[/tex], of a town after [tex]t[/tex] years is represented by the equation [tex]p = 10000(1.04)^{-t}[/tex]. Which of the following is an equivalent expression?

A. [tex]p = 10000\left(\frac{1}{25}\right)^t[/tex]

B. [tex]p = 10000\left(\frac{25}{26}\right)^t[/tex]

C. [tex]p = 10000\left(\frac{26}{25}\right)^t[/tex]

D. [tex]p = 10000\left(\frac{25}{1}\right)^t[/tex]

Answer :

We start with the equation

$$
p = 10000(1.04)^{-t}.
$$

Recall that a negative exponent means taking the reciprocal. Therefore,

$$
(1.04)^{-t} = \left(\frac{1}{1.04}\right)^t.
$$

Next, we express $1.04$ as a fraction. Notice that

$$
1.04 = \frac{26}{25}.
$$

Taking the reciprocal gives

$$
\frac{1}{1.04} = \frac{1}{\frac{26}{25}} = \frac{25}{26}.
$$

Thus, we have

$$
\left(\frac{1}{1.04}\right)^t = \left(\frac{25}{26}\right)^t.
$$

Substituting this back into the original equation, it becomes

$$
p = 10000\left(\frac{25}{26}\right)^t.
$$

Therefore, the equivalent expression is

$$
p = 10000\left(\frac{25}{26}\right)^t.
$$

Comparing this with the given options, the correct choice is option 2.

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