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Answer :
Gay Lussac's Law
P₁/T₁=P₂/T₂
25°C = 25+273 = 298 K
0.5/298 = 1.5/T₂
T₂ = 894 K = 621 °C
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A gas law known as Gay-Lussac's law asserts that a gas's pressure (when kept at a constant volume and mass) varies directly with its absolute temperature. The new temperature is 612 °C and the correct option is A.
When the mass is fixed and the volume is constant, the pressure a gas exerts is proportional to the temperature of the gas. In the year 1808, French scientist Joseph Gay-Lussac created this law. Gay-Lussac's law can be expressed mathematically as follows:
P₁ / T₁ = P₂ / T₂
25°C = 25 + 273 = 298 K
0.5 / 298 = 1.5 / T₂
T₂ = 894 K
T₂ = 894-273
T₂ = 621 °C
Thus the correct option is A.
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