Answer :

To solve the problem, we start with the pressure given in atmospheres and use the conversion factor:

[tex]$$
1 \text{ atm} = 101.325 \text{ kPa}
$$[/tex]

Given the pressure is [tex]$2.42 \text{ atm}$[/tex], we convert it to kilopascals (kPa) by multiplying by the conversion factor:

[tex]$$
\text{Pressure in kPa} = 2.42 \, \text{atm} \times 101.325 \, \frac{\text{kPa}}{\text{atm}}
$$[/tex]

Calculating this gives:

[tex]$$
\text{Pressure in kPa} \approx 245.2065 \, \text{kPa}
$$[/tex]

Rounding to a reasonable precision, we can say the pressure is approximately [tex]$245 \, \text{kPa}$[/tex].

Thus, the correct answer is [tex]$\boxed{245 \, \text{kPa}}$[/tex].

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Rewritten by : Barada