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Answer :
To solve the problem, we start with the pressure given in atmospheres and use the conversion factor:
[tex]$$
1 \text{ atm} = 101.325 \text{ kPa}
$$[/tex]
Given the pressure is [tex]$2.42 \text{ atm}$[/tex], we convert it to kilopascals (kPa) by multiplying by the conversion factor:
[tex]$$
\text{Pressure in kPa} = 2.42 \, \text{atm} \times 101.325 \, \frac{\text{kPa}}{\text{atm}}
$$[/tex]
Calculating this gives:
[tex]$$
\text{Pressure in kPa} \approx 245.2065 \, \text{kPa}
$$[/tex]
Rounding to a reasonable precision, we can say the pressure is approximately [tex]$245 \, \text{kPa}$[/tex].
Thus, the correct answer is [tex]$\boxed{245 \, \text{kPa}}$[/tex].
[tex]$$
1 \text{ atm} = 101.325 \text{ kPa}
$$[/tex]
Given the pressure is [tex]$2.42 \text{ atm}$[/tex], we convert it to kilopascals (kPa) by multiplying by the conversion factor:
[tex]$$
\text{Pressure in kPa} = 2.42 \, \text{atm} \times 101.325 \, \frac{\text{kPa}}{\text{atm}}
$$[/tex]
Calculating this gives:
[tex]$$
\text{Pressure in kPa} \approx 245.2065 \, \text{kPa}
$$[/tex]
Rounding to a reasonable precision, we can say the pressure is approximately [tex]$245 \, \text{kPa}$[/tex].
Thus, the correct answer is [tex]$\boxed{245 \, \text{kPa}}$[/tex].
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