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Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that [tex]\square[/tex] of the offspring will be heterozygous.

[tex]
\[
\begin{tabular}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{tabular}
\]
[/tex]

2. If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\square[/tex].

[tex]
\[
\begin{tabular}{|c|c|c|}
\hline
& W & W \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{tabular}
\]
[/tex]

Answer :

Let's analyze the two crosses one by one.

1. For the first cross, a heterozygous male with genotype [tex]$Ww$[/tex] is mated with a homozygous recessive female with genotype [tex]$ww$[/tex]. The Punnett square is constructed by placing the male gametes ([tex]$W$[/tex] and [tex]$w$[/tex]) along the top and the female gametes ([tex]$w$[/tex] and [tex]$w$[/tex]) along the side:

[tex]$$
\begin{array}{c|cc}
& W & w \\ \hline
w & Ww & ww \\
w & Ww & ww \\
\end{array}
$$[/tex]

In this square there are 4 equally likely outcomes: two are [tex]$Ww$[/tex] (heterozygous) and two are [tex]$ww$[/tex] (homozygous recessive). Therefore, the probability that an offspring is heterozygous ([tex]$Ww$[/tex]) is

[tex]$$
\frac{2}{4} = 0.5.
$$[/tex]

2. In the second cross, a heterozygous individual ([tex]$Ww$[/tex]) is crossed with a homozygous dominant individual ([tex]$WW$[/tex]). The Punnett square for this cross is:

[tex]$$
\begin{array}{c|cc}
& W & W \\ \hline
W & WW & WW \\
w & Ww & Ww \\
\end{array}
$$[/tex]

From this square, there are 4 equally likely outcomes: two outcomes are [tex]$WW$[/tex] (homozygous dominant) and two outcomes are [tex]$Ww$[/tex] (heterozygous). None of these outcomes is homozygous recessive ([tex]$ww$[/tex]). Thus, the probability of obtaining a homozygous recessive offspring is

[tex]$$
0.
$$[/tex]

In summary:
- The chance that an offspring from the first cross is heterozygous is [tex]$0.5$[/tex].
- The probability of having a homozygous recessive offspring in the second cross is [tex]$0$[/tex].

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