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Answer :
[tex]\begin{gathered} D=10log(\frac{I}{Io}) \\ \\ D=10log(\frac{10^{0.5}}{10^{\text{ -12}\frac{}{}}}) \\ \\ D=10log(10^{11.5}) \\ D=10(11.5)=115 \end{gathered}[/tex]
The answer would be 115
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