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Answer :
the probability of getting a mean temperature of 98.2 or lower is 0.259
Obtaining the Z-score
- Z-score = (x - mean)/ standard deviation
- x = 98.2
- Mean = 98.6
- standard deviation = 0.62
Z-score = (98.2-98.6)/0.62= -0.645
Using a standard normal distribution table or a Z-probability calculator:
- P(Z ≤ -0.645) = 0.259
Hence, the probability of getting a mean temperature of 98.2 or lower is 0.259
Learn more on Zscore :brainly.com/question/25638875
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