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Answer :
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We have a proportional relationship between the time Franco spends shelling peas (in minutes) and the weight of the peas in pounds. The relationship is described by the equation:
[tex]\[ y = 0.4x \][/tex]
Here, [tex]\( y \)[/tex] is the weight of the peas in pounds, and [tex]\( x \)[/tex] is the time in minutes.
The problem asks us to find out how long it takes Franco to shell 18 pounds of peas. So, we need to determine the value of [tex]\( x \)[/tex] when [tex]\( y = 18 \)[/tex].
We can use the equation to solve for [tex]\( x \)[/tex]:
1. Start with the equation:
[tex]\[ y = 0.4x \][/tex]
2. Substitute the given [tex]\( y \)[/tex] value (18 pounds) into the equation:
[tex]\[ 18 = 0.4x \][/tex]
3. To isolate [tex]\( x \)[/tex], divide both sides of the equation by 0.4:
[tex]\[ x = \frac{18}{0.4} \][/tex]
4. Calculate [tex]\( x \)[/tex]:
[tex]\[ x = 45.0 \][/tex]
So, it takes Franco 45.0 minutes to shell 18 pounds of peas.
We have a proportional relationship between the time Franco spends shelling peas (in minutes) and the weight of the peas in pounds. The relationship is described by the equation:
[tex]\[ y = 0.4x \][/tex]
Here, [tex]\( y \)[/tex] is the weight of the peas in pounds, and [tex]\( x \)[/tex] is the time in minutes.
The problem asks us to find out how long it takes Franco to shell 18 pounds of peas. So, we need to determine the value of [tex]\( x \)[/tex] when [tex]\( y = 18 \)[/tex].
We can use the equation to solve for [tex]\( x \)[/tex]:
1. Start with the equation:
[tex]\[ y = 0.4x \][/tex]
2. Substitute the given [tex]\( y \)[/tex] value (18 pounds) into the equation:
[tex]\[ 18 = 0.4x \][/tex]
3. To isolate [tex]\( x \)[/tex], divide both sides of the equation by 0.4:
[tex]\[ x = \frac{18}{0.4} \][/tex]
4. Calculate [tex]\( x \)[/tex]:
[tex]\[ x = 45.0 \][/tex]
So, it takes Franco 45.0 minutes to shell 18 pounds of peas.
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