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On a piece of paper (or anything you can use to solve this) complete a dihybrid cross for SR, sR, Sr and sr with SR, sR, Sr, and sr. how many of the offspring will be SSrr?

On a piece of paper or anything you can use to solve this complete a dihybrid cross for SR sR Sr and sr with SR

Answer :

Only one individual of the offspring will be SSrr.

The correct answer is 1.

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Rewritten by : Barada

Final answer:

In a dihybrid cross between parents with different genotypes, using a Punnett square can help determine the genotypes of the offspring. Out of the 16 possible genotypes, only 1 will have the genotype SSrr.

Explanation:

In a dihybrid cross between parents with genotypes SR, sR, Sr, and sr, we can use a Punnett square to determine the genotypes of the offspring. The genotypes of the offspring will be in a 3:1 ratio for each genotype combination. Therefore, there will be 1 out of 16 offspring that will have the genotype SSrr.

In a dihybrid cross, two traits controlled by different genes are considered simultaneously. Using a Punnett square is a helpful tool to visualize the potential combinations of alleles in the offspring.

Out of the 16 possible genotypes that can result from a dihybrid cross, only one combination will have the specific genotype SSrr. This means that the probability of obtaining the SSrr genotype is 1 out of 16 or 1/16.

This emphasizes the importance of understanding probability in genetics, as it allows us to predict the likelihood of specific genotypes appearing in the offspring of a dihybrid cross. Your explanation accurately captures this concept.

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