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The average weight of 20 students in a certain school was found to be 165 lbs with a standard deviation of 4.5 lbs.

A) Construct a 90% confidence interval for the population mean.

Answer :

A. The 90% confidence interval for the population mean is (162.91,167.09)

B. The value Margin of error is 7.42

C. The interpretation of the confidence level obtain from (a) is there is a 90% chance that the interval (162.91,167.09) contains the true population mean.

How can we determine the values given above?

a) A 90% confidence interval for the population mean can be constructed using the following formula:

(sample mean) ± (critical value) x (standard deviation of the mean)

The critical value is determined by the level of confidence and the sample size. For a 90% confidence level and a sample size of 20, the critical value is 1.645.

Therefore, the 90% confidence interval for the population mean is:

165 ± (1.645 x 4.5)

which is (162.91,167.09)

b) The margin of error is the critical value x the standard deviation of the mean, or 1.645 x 4.5 = 7.42.

c) A 90% confidence interval means that if we were to repeat this process many times, 90% of the intervals constructed would contain the true population mean. In other words, there is a 90% chance that the interval (162.91,167.09) contains the true population mean.

Therefore, the correct answer is as given above. It can then be concluded that the values given for 90% confidence interval, margin of error and it's interpretation are as given.

learn more about margin of error: https://brainly.com/question/10218601

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