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Answer :
Let's break down the problem step-by-step.
First Scenario:
We are crossing a heterozygous male with genotype Ww and a homozygous recessive female with genotype ww.
To determine the potential genotypes of the offspring, we use a Punnett square:
```
W w
------------
w | Ww ww
w | Ww ww
```
Here's how to read the Punnett square:
- The male's alleles (W and w) are placed along the top.
- The female's alleles (w and w) are placed down the side.
You fill in the squares by combining the alleles from the top and the side.
From this, the possible genotypes of the offspring are:
- Ww (heterozygous)
- ww (homozygous recessive)
In total, there are 4 squares:
- Two of these squares result in Ww (heterozygous).
- Two of these squares result in ww (homozygous recessive).
The chance of having a heterozygous (Ww) offspring is 2 out of 4 squares, which simplifies to a probability of 0.5 or 50%.
Second Scenario:
Now, consider the cross between a homozygous dominant male with genotype WW and a homozygous dominant female with genotype WW.
The potential genotypes are:
```
W W
------------
W | WW WW
W | WW WW
```
In this scenario:
- All offspring will have the genotype WW (homozygous dominant).
Since the genotype ww (homozygous recessive) is not possible, the probability of having a homozygous recessive (ww) offspring is 0.
To summarize:
- In the first scenario, the probability of having a heterozygous offspring is 0.5.
- In the second scenario, the probability of having a homozygous recessive offspring is 0.
First Scenario:
We are crossing a heterozygous male with genotype Ww and a homozygous recessive female with genotype ww.
To determine the potential genotypes of the offspring, we use a Punnett square:
```
W w
------------
w | Ww ww
w | Ww ww
```
Here's how to read the Punnett square:
- The male's alleles (W and w) are placed along the top.
- The female's alleles (w and w) are placed down the side.
You fill in the squares by combining the alleles from the top and the side.
From this, the possible genotypes of the offspring are:
- Ww (heterozygous)
- ww (homozygous recessive)
In total, there are 4 squares:
- Two of these squares result in Ww (heterozygous).
- Two of these squares result in ww (homozygous recessive).
The chance of having a heterozygous (Ww) offspring is 2 out of 4 squares, which simplifies to a probability of 0.5 or 50%.
Second Scenario:
Now, consider the cross between a homozygous dominant male with genotype WW and a homozygous dominant female with genotype WW.
The potential genotypes are:
```
W W
------------
W | WW WW
W | WW WW
```
In this scenario:
- All offspring will have the genotype WW (homozygous dominant).
Since the genotype ww (homozygous recessive) is not possible, the probability of having a homozygous recessive (ww) offspring is 0.
To summarize:
- In the first scenario, the probability of having a heterozygous offspring is 0.5.
- In the second scenario, the probability of having a homozygous recessive offspring is 0.
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