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Answer :
Answer: Around 8038 lbs * ft
Explanation:
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The total moment produced by all the weights is given by the following formula:Resultant moment = sum of moments of all the weights about point A= (1500 * 15) - (200 * 6) - (176 * 8)= 22500 - 1200 - 1408= 19892 lb·ft (Clockwise)Therefore, the resultant moment produced by all the weights about point A is 19892 lb·ft (Clockwise).
The given mass values are as follows: The boom AB has a mass of 1500 lb, the cage BCD has a mass of 200 lb, and the man has a mass of 176 lb.The centers of gravity for the weights are as follows: G1 for the boom AB, G2 for the cage BCD, and G3 for the man. The resultant moment produced by all the weights about point A needs to be determined.
The distance AB from point A to point G1 is 15 ftThe distance CD from point A to point G2 is 6 ftThe distance from point A to point G3 is 8 ftLet's calculate the moments of the individual weights about point A first:Moment of weight AB about A = Weight of AB * distance from A to G1= 1500 * 15= 22500 lb·ft (Clockwise)Moment of weight BCD about A = Weight of BCD * distance from A to G2= 200 * 6= 1200 lb·ft (Counterclockwise)Moment of weight of man about A = Weight of man * distance from A to G3= 176 * 8= 1408 lb·ft (Counterclockwise).
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