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One week, a construction worker bought [tex]$40 \frac{1}{10}$[/tex] pounds of nails. The next week, he bought [tex]$2 \frac{1}{2}$[/tex] times as many nails as the week before. How many pounds of nails did he buy the second week?

A. [tex]$16 \frac{1}{25}$[/tex] lb
B. [tex]$99 \frac{1}{4}$[/tex] lb
C. [tex]$80 \frac{1}{20}$[/tex] lb
D. [tex]$100 \frac{1}{4}$[/tex] lb

Answer :

To find out how many pounds of nails the construction worker bought the second week, we need to perform a few calculations:

1. First Week Purchase:
- The construction worker initially bought [tex]\(40 \frac{1}{10}\)[/tex] pounds of nails. This can be converted into a decimal as:
[tex]\[
40 \frac{1}{10} = 40 + 0.1 = 40.1 \text{ pounds}
\][/tex]

2. Next Week's Purchase:
- The following week, the worker bought [tex]\(2 \frac{1}{2}\)[/tex] times as many nails as the first week. This means we multiply the first week's amount by [tex]\(2 \frac{1}{2}\)[/tex], which can be converted into a decimal:
[tex]\[
2 \frac{1}{2} = 2 + 0.5 = 2.5
\][/tex]

3. Calculate the Second Week's Purchase:
- To find the amount of nails bought in the second week, multiply the first week's amount by the multiplier from the second week:
[tex]\[
40.1 \times 2.5 = 100.25 \text{ pounds}
\][/tex]

Therefore, the construction worker bought [tex]\(100 \frac{1}{4}\)[/tex] pounds of nails the second week. The correct answer is:

(D) [tex]\(100 \frac{1}{4} \, \text{lb}\)[/tex]

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