Answer :

Given :

Mass of Ba(OH)₂ , m = 35.5 g.

Volume of mixture, V = 325 mL = 0.325 L.

To Find :

The molarity of a solution.

Solution :

We know, molarity of a solution is given by :

[tex]M = \dfrac{Given \ Weight}{Molecular\ Mass\times Volume( L ) }[/tex]

We know, molecular mass of Ba(OH)₂ is given by :

M.M. = 171 g/mol

Putting all these values in given equation, we get :

[tex]M = \dfrac{35.5}{171\times 0.325}\ M\\\\M = 0.64\ M[/tex]

Hence, this is the required solution.

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Rewritten by : Barada