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How much energy is required to vaporize 1.5 kg of aluminum? (Refer to the table of latent heat values.)

A. 600 kJ
B. 165 J
C. 7095 kJ
D. 733 kJ

Answer :

To determine how much energy is required to vaporize 1.5 kg of aluminum, we need to use the formula:

[tex]\[ \text{Energy required} = \text{mass} \times \text{latent heat of vaporization} \][/tex]

Here are the steps:

1. Identify the mass of the aluminum:
- The given mass is 1.5 kg.

2. Identify the latent heat of vaporization for aluminum:
- The latent heat of vaporization is a property of a substance that describes the amount of heat required to turn a certain mass of a solid into vapor, without a change in temperature. For aluminum, the latent heat of vaporization is typically around 10,300 kJ/kg.

3. Calculate the energy required:
- Multiply the mass of the aluminum by the latent heat of vaporization:
[tex]\[
1.5 \, \text{kg} \times 10,300 \, \text{kJ/kg} = 15,450 \, \text{kJ}
\][/tex]

Therefore, the amount of energy required to vaporize 1.5 kg of aluminum is 15,450 kJ. Keep in mind that this amount does not match any of the provided multiple-choice options. It's possible that there was an error in the options given or in the calculation of one of the values. Double-checking table values for the latent heat of vaporization might help in a classroom setting.

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