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Answer :
Final answer:
The primary sludge volume in an activated sludge facility is most nearly 239,680 ft3/day.
Explanation:
To calculate the primary sludge volume, we need to multiply the sludge solids content, specific gravity, and the flow rate of the primary sludge.
Given:
First, we need to convert the flow rate from MGD to ft3/day:
1 MGD = 1,000,000 gallons/day
1 gallon = 7.48 ft3
Therefore, 1 MGD = 1,000,000 * 7.48 ft3/day = 7,480,000 ft3/day
Now, we can calculate the primary sludge volume:
Primary sludge volume = Primary sludge solids content * Specific gravity * Flow rate of primary sludge
= 4% * 1.0 * 0.8 MGD * 7,480,000 ft3/day
Converting MGD to ft3/day:
= 0.04 * 0.8 * 7,480,000 ft3/day
Calculating the primary sludge volume:
= 239,680 ft3/day
Therefore, the primary sludge volume is most nearly 239,680 ft3/day.
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