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The atomic mass of potassium is 39.1. What is the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium?

A. [tex]\quad 39.1 \, \text{mg}[/tex]

B. [tex]\quad 39.1 \, \text{g}[/tex]

C. [tex]\quad 39.1 \, \text{kg}[/tex]

D. [tex]\quad 6.02 \times 39.1 \, \text{mg}[/tex]

E. [tex]\quad 6.02 \times 39.1 \, \text{g}[/tex]

Answer :

We start by noting that the given number of atoms is equal to Avogadro's number, which is
[tex]$$6.02 \times 10^{23}.$$[/tex]

This means that there is exactly one mole of potassium. Since one mole of potassium weighs its atomic mass, we have:

[tex]$$\text{Mass} = 39.1 \text{ grams.}$$[/tex]

Thus, the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium is [tex]$\boxed{39.1 \text{ g}}$[/tex].

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