Answer :

The output work and input work are 806.4 joules.

If the load is lifted a total distance of 1.37m, we need to calculate the output work and input work. We can use the work formula:

W = F × d

where d is the distance traveled, F is the force used, and W is the work completed.


Let's assume the mass of the load is 60kg and use the gravitational acceleration g = 9.81m/s²:

F = mg = 60 kg × 9.81 m/s² = 588.6 N

Now we can find the output work:

W_output = F × d = 588.6 N × 1.37 m = 806.4 J (Joules)

The input work could vary based on the efficiency of the lifting mechanism. If the efficiency (η) is not provided, we assume an ideal scenario with 100% efficiency (η = 1):

W_input = W_output / η = 806.4 J / 1 = 806.4 J

Therefore, the input work and output work are equal, both being 806.4 joules in this ideal scenario.

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Rewritten by : Barada