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Answer :
To find the mass of the truck, we start with the definition of momentum, which is given by the formula
[tex]$$
p = m \cdot v,
$$[/tex]
where
[tex]\( p \)[/tex] is the momentum,
[tex]\( m \)[/tex] is the mass, and
[tex]\( v \)[/tex] is the velocity.
We are given:
[tex]\( p = 125,\!000 \, \text{kg} \cdot \frac{\text{m}}{\text{s}} \)[/tex] and [tex]\( v = 22.0 \, \text{m/s} \)[/tex].
To isolate the mass [tex]\( m \)[/tex], we rearrange the formula:
[tex]$$
m = \frac{p}{v}.
$$[/tex]
Substituting the provided values into the formula, we have
[tex]$$
m = \frac{125,\!000}{22.0}.
$$[/tex]
Evaluating the division,
[tex]$$
m \approx 5681.82 \, \text{kg}.
$$[/tex]
Rounding to the nearest option, the mass of the truck is approximately
[tex]$$
5680 \, \text{kg}.
$$[/tex]
Thus, the correct answer is [tex]\( 5680 \, \text{kg} \)[/tex].
[tex]$$
p = m \cdot v,
$$[/tex]
where
[tex]\( p \)[/tex] is the momentum,
[tex]\( m \)[/tex] is the mass, and
[tex]\( v \)[/tex] is the velocity.
We are given:
[tex]\( p = 125,\!000 \, \text{kg} \cdot \frac{\text{m}}{\text{s}} \)[/tex] and [tex]\( v = 22.0 \, \text{m/s} \)[/tex].
To isolate the mass [tex]\( m \)[/tex], we rearrange the formula:
[tex]$$
m = \frac{p}{v}.
$$[/tex]
Substituting the provided values into the formula, we have
[tex]$$
m = \frac{125,\!000}{22.0}.
$$[/tex]
Evaluating the division,
[tex]$$
m \approx 5681.82 \, \text{kg}.
$$[/tex]
Rounding to the nearest option, the mass of the truck is approximately
[tex]$$
5680 \, \text{kg}.
$$[/tex]
Thus, the correct answer is [tex]\( 5680 \, \text{kg} \)[/tex].
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