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Answer :
SOLUTION
Let the height of the smaller heap be h
Since the heaps are similar it follows:
[tex]\frac{128}{250}=\frac{h}{70}[/tex]Solve for h
[tex]\begin{gathered} h=\frac{70\times128}{250} \\ h=35.84 \end{gathered}[/tex]Therefore the height of the smaller heap is 35.84kg
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