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Answer :
Quadratic equations can have two solutions, then, we can build one whose 2 solutions are 12 and 116.
It can be built as follows:
[tex](x-12)(x-116)=0[/tex]The equation is a product of two expressions equal to 0. When a product is 0, we know that either the first parenthesis or the second one is equal to 0. Then, the solution x for the above equation can be:
[tex]\begin{gathered} (x-12)=0 \\ x=12 \end{gathered}[/tex]Or well:
[tex]\begin{gathered} x-116=0 \\ x=116 \end{gathered}[/tex]Both 12 and 116 solve the equation. We can rewrite the equation by solving the multiplication:
[tex]\begin{gathered} (x-12)(x-116)=0 \\ x^2-12x-116x+12\cdot116=0 \\ x^2-128x+1392=0 \end{gathered}[/tex]Then, an equation that has as solutions both 12 and 116 could be:
[tex]x^2-128x+1392=0[/tex]If we plug either value on the x of the equation we will see that the equality is fulfilled. Alternatively, if we solve the quadratic equation with the general formula, we will also obtain that the x can take the values of both 12 and 116
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