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Answer :
To solve the problem of how many [tex]\(\frac{1}{4}\)[/tex] meter rods can be obtained from a rod that is [tex]\(\frac{45}{12}\)[/tex] meters long, follow these steps:
1. Understand the problem: You need to determine how many smaller rods of length [tex]\(\frac{1}{4}\)[/tex] meters can be cut from a larger rod that is [tex]\(\frac{45}{12}\)[/tex] meters long.
2. Convert the fractions to decimals for easier calculation:
- First, let’s convert [tex]\(\frac{45}{12}\)[/tex] to a decimal:
[tex]\[\frac{45}{12} = 3.75\][/tex]
- Next, convert [tex]\(\frac{1}{4}\)[/tex] to a decimal:
[tex]\[\frac{1}{4} = 0.25\][/tex]
3. Divide the length of the larger rod by the length of the smaller rods:
- To find out how many [tex]\(\frac{1}{4}\)[/tex] meter rods can fit into a [tex]\(\frac{45}{12}\)[/tex] meter rod, divide the length of the larger rod by the length of one smaller rod:
[tex]\[3.75 \div 0.25 = 15\][/tex]
4. Conclusion: You can obtain 15 rods of [tex]\(\frac{1}{4}\)[/tex] meter length from a rod that is [tex]\(\frac{45}{12}\)[/tex] meters long.
So, [tex]\(\boxed{15}\)[/tex] rods of [tex]\(\frac{1}{4}\)[/tex] meter each can be cut from a [tex]\(\frac{45}{12}\)[/tex] meter rod.
1. Understand the problem: You need to determine how many smaller rods of length [tex]\(\frac{1}{4}\)[/tex] meters can be cut from a larger rod that is [tex]\(\frac{45}{12}\)[/tex] meters long.
2. Convert the fractions to decimals for easier calculation:
- First, let’s convert [tex]\(\frac{45}{12}\)[/tex] to a decimal:
[tex]\[\frac{45}{12} = 3.75\][/tex]
- Next, convert [tex]\(\frac{1}{4}\)[/tex] to a decimal:
[tex]\[\frac{1}{4} = 0.25\][/tex]
3. Divide the length of the larger rod by the length of the smaller rods:
- To find out how many [tex]\(\frac{1}{4}\)[/tex] meter rods can fit into a [tex]\(\frac{45}{12}\)[/tex] meter rod, divide the length of the larger rod by the length of one smaller rod:
[tex]\[3.75 \div 0.25 = 15\][/tex]
4. Conclusion: You can obtain 15 rods of [tex]\(\frac{1}{4}\)[/tex] meter length from a rod that is [tex]\(\frac{45}{12}\)[/tex] meters long.
So, [tex]\(\boxed{15}\)[/tex] rods of [tex]\(\frac{1}{4}\)[/tex] meter each can be cut from a [tex]\(\frac{45}{12}\)[/tex] meter rod.
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