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How much must the diameter of a [tex]\frac{7}{8}[/tex]-inch shaft be reduced if the diameter is to be [tex]\frac{39}{48}[/tex]-inch?

A. [tex]\frac{32}{40}[/tex]
B. [tex]\frac{1}{16}[/tex]
C. [tex]\frac{4}{48}[/tex]
D. [tex]\frac{7}{6}[/tex]

Answer :

To find out how much the diameter of the 7/8-inch shaft must be reduced to become 39/48-inch, we need to determine the difference between the original diameter and the desired diameter.

Let's break it down step-by-step:

1. Original Diameter: The original diameter of the shaft is [tex]\( \frac{7}{8} \)[/tex] inches.

2. Desired Diameter: The desired diameter is [tex]\( \frac{39}{48} \)[/tex] inches.

3. Calculate the Reduction: To find the reduction needed, subtract the desired diameter from the original diameter:

[tex]\[
\text{Reduction} = \frac{7}{8} - \frac{39}{48}
\][/tex]

4. Make the Denominators the Same: Before we can subtract the fractions, we need the same denominator. The least common denominator (LCD) of 8 and 48 is 48.

- Convert [tex]\(\frac{7}{8}\)[/tex] to have a denominator of 48:

[tex]\[
\frac{7}{8} = \frac{7 \times 6}{8 \times 6} = \frac{42}{48}
\][/tex]

5. Perform the Subtraction: Now that both fractions have the same denominator, subtract:

[tex]\[
\frac{42}{48} - \frac{39}{48} = \frac{42 - 39}{48} = \frac{3}{48}
\][/tex]

6. Simplify the Fraction: The fraction [tex]\( \frac{3}{48} \)[/tex] can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 3:

[tex]\[
\frac{3}{48} = \frac{3 \div 3}{48 \div 3} = \frac{1}{16}
\][/tex]

Therefore, the diameter must be reduced by [tex]\( \frac{1}{16} \)[/tex] inch, which corresponds to option b. 1/16.

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