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A computer randomly puts a point inside the rectangle. What is the probability that the point does not land in triangle T?

A. 1/6

B. 1/3

C.3/8

D.5/6

A computer randomly puts a point inside the rectangle What is the probability that the point does not land in triangle T A 1 6

Answer :

The probability that the point does not land in triangle T is A. 1/6.

Here's how we can arrive at the solution:

Visualize the areas:

The rectangle has a total area of 6 units (2 units in height and 3 units in width).

Triangle T occupies half of the rectangle's area, 3 units.

The remaining area outside of triangle T is also 3 units.

Probability concept:

Probability is the ratio of favorable outcomes to total possible outcomes.

In this case, the favorable outcome is the point landing outside of triangle T.

The total possible outcomes are all points within the rectangle.

Apply the formula:

Probability of point not landing in triangle T = (Area outside triangle T) / (Total area of rectangle)

Probability = 3 units / 6 units

Probability = 1/6

Therefore, the probability that the point does not land in triangle T is 1/6.

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